Question #75958

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Answer 1 · 2017-05-22T04:27:46

#x = -1#

use completing a square to find axis of symetry.

#y = 4 x^2 + 8 x - 2#

#y = 4(x^2 +2x) -2#

#y = 4(x + 1)^2 -4(1^2) - 2#

#y = 4(x + 1)^2 - 6#

axis of symetry is when #(x + 1) = 0#
therefore axis symetry is #x = -1#

Answer 2 · 2017-05-22T04:44:29

x = -1

#y = 4x^2 + 8x - 2#
x-coordinate of the axis of symmetry:
#x = -b/(2a) = -8/8 = - 1#