How do you integrate #int (4x+3) / (x - 1)^2dx# using partial fractions?
1 Answer
May 22, 2017
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Explanation:
By substituting
Split the integrals to make it easier.
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#4 int 1/(x-1)dx = 4ln|x-1| + c_1# Integration of inverse functions. -
#7 int(x-1)^-2dx = 7*-1*(x-1)^-1 + c_2# Using reverse chain rule.
Therefore,