Question

How do you find the quotient `(4y-8)/(y+1)div(y-2)`?

Answer 1

`(4y-8)/(y+1) -: (y-2) = 4/(y+1)`

Explanation:

To do this problem we need to simplify the top or the numerator a bit more than it is already. Mostly we need to take out a 4. It might seem pointless at first, but once we do it everything will become clear:

`4y-8 = 4(y-2)`

Now we can rewrite the problem so it looks like this:

`(4(y-2))/(y+1) -: (y-2)`

Now we can solve it, as we know that
`(y-2)/(y-2) = 1`

So:
`(4(y-2))/(y+1) -: (y-2) = 4/(y+1)`

Hope that helps!