If an object with uniform acceleration (or deceleration) has a speed of #2 m/s# at #t=0# and moves a total of 90 m by #t=6#, what was the object's rate of acceleration?

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Answer 1 · 2017-05-30T06:55:35

The rate of acceleration is #=4.33ms^-2#

The initial speed is #u=2ms^-1#

The distance is #s=90m#

The time is #t=6s#

The acceleration is #a=?#

We apply the equation of motion

#s=ut+1/2at^2#

Therefore,

#1/2at^2=s-ut#

#a=(s-ut)/(1/2t^2)#

#=(90-6*2)/(1/2*6^2)#

#=78/18#

#=4.33ms^-2#