How do you use the quadratic formula to solve x^2+5x-2=0?

1 Answer
May 31, 2017

x Can either = -4.56155 or -0.43845

Explanation:

ax^2 + bx + c = 0

x = (-b+-sqrt(b^2 + 4ac))/(2a

ax^2 + 5x + -2 = 0

a = 1
b = 5
c = -2

x = (-5+-sqrt(5^2 + 4 xx 1 xx -2))/(2 xx 1

x = (-5+-sqrt(25 + -8))/(2

x = (-5+-sqrt17)/(2

x_1 = (-5 - 4.1231)/(2

x_1 = (-9.1231)/(2

color(blue)(x_1 = -4.56155

x_2 = (-5 + 4.1231)/(2

x_2 = -0.8769/(2

color(blue)(x_2 = -0.43845