How do you simplify and find the excluded value of # (9y + 8) / (y) #?

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Answer 1 · 2017-06-01T19:57:24

See a solution process below:

Because we cannot divide by #0#, the excluded value is #y = 0#.

To simplify, we can split the fraction and cancel common terms as follows:

#(9y + 8)/y =>#

#(9y)/y + 8/y =>#

#(9color(red)(cancel(color(black)(y))))/color(red)(cancel(color(black)(y))) + 8/y =>#

#9 + 8/y#

Answer 2 · 2017-06-01T20:03:45

#9+8/y#

Excluded value #-> y=0#

This is the same as: #" "(9y)/y+8/y " "->" "9+8/y#

This 'expression' (no equals sign) becomes undefined at #y=0# thus #y=0# is an excluded value giving rise to an asymptote.

As #y# becomes increasingly positive or negative then #8/y# tend to 0. So we end up with just 9

Tony B