How do you solve #x^2 - 8x + 2 = 0# using the quadratic formula?

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Answer 1 · 2017-06-03T10:36:11

7.74, 0.26

As per quadratic formula, #x =[-b+-sqrt(b^2-4ac)]/[2a] # here, a = 1, b = - 8 & c= 2

Put all these values, we get #x = [-(-8)+- sqrt{(-8)^2-4*1*2}]/[2*1]#

#rArr x = [+8 +- sqrt(64-8)]/2#

#rArr x = [8+- sqrt56]/2#

#rArr x = [8+-7.48]/2#

#rArr x = (8+7.48)/2, (8-7.48)/2#

#rArr x = 15.48/2, 0.52/2#

#rArr x = 7.74, 0.26#