The gas inside of a container exerts 9 Pa of pressure and is at a temperature of 35 ^o K. If the temperature of the gas changes to 20 ^oK with no change in the container's volume, what is the new pressure of the gas?

1 Answer
Jun 5, 2017

5 "Pa"

Explanation:

To solve this problem, we can use the pressure-temperature relationship of gases, illustrated by Gay-Lussac's law:

(P_1)/(T_1)=(P_2)/(T_2)

Let's rearrange this equation to solve for the final pressure, P_2:

P_2 = (P_1T_2)/(T_1)

Plugging in known values, we have

P_2 = ((9"Pa")(20cancel("K")))/(35cancel("K")) = color(red)(5) color(red)("Pa"

rounded to one significant figure, the lowest amount given in the problem.