How do you graph #x+y=5# using intercepts?
1 Answer
Jun 6, 2017
Plot points and connect the dots.
Explanation:
First, plot the
This gives the point
graph{((x-5)^2+(y-0)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.21]}
Next, plot the
This gives the point
graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.51]}
Finally, draw a line connecting the two points on the graph. The solution looks like this:
graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)(x+y-5)=0 [-1.904, 15.874, -3.68, 5.51]}