A ball with a mass of #140 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #42 (kg)/s^2# and was compressed by #5/6 m# when the ball was released. How high will the ball go?

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Answer 1 · 2017-06-07T06:55:59

The height is #=10.63m#

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The spring constant is #k=42kgs^-2#

The compression is #x=5/6m#

The potential energy in the spring is

#PE=1/2*42*(5/6)^2=14.58J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

#PE_(ball)=14.58=0.14*9.8*h#

#h=14.58*1/(0.14*9.8)#

#=10.63m#