How do you write the equation of a line that passes through (-4, 3) and (2, 6)?

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Answer 1 · 2017-06-07T13:32:57

See below.

We first need to find the slope of the line.

slope#=(6-3)/(2-(-4))=3/6=1/2#

We know that the equation of a line takes on the form #y=mx+b#, where #m# is the slope and #b# is the #y#-intercept.

Thus, we can plug in our answer to get:

#y=1/2x+b#

However, we know a point #(x,y)# on this line-- #(2,6)#. We can plug this in as well.

#6=1/2(2)+b#

#6=1+b#

#b=5#.

So, our final equation is:

#y=1/2x+5#