A container with a volume of #21 L# contains a gas with a temperature of #150^o K#. If the temperature of the gas changes to #120 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-06-08T18:31:36

The volume is #=16.8L#

Apply Charles' Law

#V_1/T_1=V_2/T_2#

The initial volume is #V_1=21L#

The initial temperature is #T_1=150K#

The final temperature is #T_2=120K#

The final volume is

#V_2=T_2/T_1*V_1#

#=120/150*21=16.8L#