How do you solve #2/(x-1) - 2/3 =4/(x+1)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Binayaka C. Jun 10, 2017 Solution : #x=2 or x=-5# Explanation: # 2/(x-1) -2/3 = 4/(x+1) #. Multiplying by #3(x-1)(x+1)# on both side we get, # 2*3*(x+1) -2(x^2-1) = 4*3*(x-1) # or #6x+6-2x^2+2=12x-12 or 2x^2+12x-6x-12-8 =0# or #2x^2+6x-20=0 or x^2 +3x -10=0 or x^2+5x-2x-10=0# or # x(x+5) -2(x+5) =0 or (x+5)(x-2)=0 :.#either # x-2=0 :. x=2 # or # x+5=0 :. x= -5# Solution : #x=2 or x=-5# [Ans] Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1211 views around the world You can reuse this answer Creative Commons License