How do you write #(17a^3)/a^7# using only positive exponents?

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Answer 1 · 2017-06-11T11:40:06

It is already in a positive exponent format, merely simplify it to #17/a^4#.

There are no negative powers of a, therefore it already satisfies the question.

To simplify it, cross out the #a^3# and the #a^7# so that it becomes #a^4# in the denominator.

Therefore, the simplified answer is #17/a^4#.

Answer 2 · 2017-06-11T11:41:18

#(17)/a^4#

To keep it as a positive exponent, just leave it as a fraction.

#a^(3-7) = a^-4#

#17/a^4#