Question

If `f(x) = sin(x)` and `g(x) = sin(-x)`, what is `h(x) = f(x) + g(x)`?

Answer 1

`h(x)=0`

Explanation:

`f(x)=sinx`

`g(x)=sin(-x)`

`sinx` is an odd function, so `sin(-x)-=-sinx`

`thereforeg(x)=-sinx`

`h(x)=f(x)+g(x)=sinx-sinx=0`