How do you solve #7+19m=3m+2#?

2 Answers
Jun 12, 2017

#m=-5/16#

Explanation:

Subtract #7# and #3m# from both sides:

#cancel(7-7)+19m-3m=cancel(3m-3m)+2-7#

#19m-3m=2-7#

Combine like terms:

#16m=-5#

Divide #16m# to both sides to isolate #m#

#cancel16/cancel16m=-5/16#

#m=-5/16#

Jun 12, 2017

First, by transposing method, we'll send the #3m# to LHS and #7# to RHS
#19m - 3m = -7 +2#
and, now, we'll solve them (because we can)
#16m = -5#
and, by transposing method, again,
#m = frac (-5) 16#