What is #8(3+4)-2*8-:(5-3)#?

Question

2529 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-30T18:43:50

See a solution process below:

First, execute the operations within the Parenthesis:

#8(color(red)(3 + 4)) - 2 * 8 -: (color(red)(5 - 3)) => #

#8 * 7 - 2 * 8 -: 2#

Next, execute the Multiplication and Division operations from left to right:

#color(red)(8 * 7) - 2 * 8 -: 2 =>#

#56 - color(red)(2 * 8) -: 2 =>#

#56 - color(red)(16 -: 2) =>#

#56 - 8#

Now, execute the Subtraction operation:

#56 - 9 => 48#

Answer 2 · 2017-06-12T11:49:00

#48#

#8(3+4)-2*8-:(5-3)#

#:.=8(7)-16-:2#

#:.=56-8#

#:.=48#