Question

How do you solve `c^2 = 111`?

Answer 1

`\pm\sqrt{111}`

Explanation:

`c^2=111`
`c^2-111=0`
`(c+\sqrt{111})(c-\sqrt{111})=0`
`c+\sqrt{111}=0`
`c=-\sqrt{111}`
`c-\sqrt{111}=0`
`c=\sqrt{111}`
`c=\pm\sqrt{111}`