Question

Acceleration is defined as the rate of change of velocity with time. If an object accelerates from `10` `ms^-1` to `20` `ms^-1` in `5` `s`, what is the magnitude of its acceleration?

Answer 1

The definitions you've shared in words there can be turned into an equation:

`a = (\Delta v)/(\Delta t) = (v-u)/t`

where a is the acceleration, u is the initial velocity and v is the final velocity. in this case:

equation:

`a = (v-u)/t = (20-10)/5 = 2` `ms^-2`

Answer 2

`2 m/(s^2)`

Explanation:

You just have to do the calculation
`a= (v_2-v_1)/(t_2-t_1)= (20 m/s-10m/s)/ (5s)= 2 m/(s^2)`