How do you solve #12x-4=32#?

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Answer 1 · 2017-06-14T18:33:55

#x=3#

First, add four to both sides which will leave you with

#12x=36#

Next, divide by #12# on both sides leaving you with

#x=3#

Answer 2 · 2017-06-14T18:34:53

See a solution process below:

Step 1) Add #color(red)(4)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#12x - 4 + color(red)(4) = 32 + color(red)(4)#

#12x - 0 = 36#

#12x = 36#

Step 2) Divide each side of the equation by #color(red)(12)# to solve for #x# while keeping the equation balanced:

#(12x)/color(red)(12) = 36/color(red)(12)#

#(color(red)(cancel(color(black)(12)))x)/cancel(color(red)(12)) = 3#

#x = 3#