How do you graph the line given (2,-1), m = -1/3?

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Answer 1 · 2017-06-14T19:08:20

$y = - \frac{1}{3} x - \frac{1}{3}$ $y=-1/3x-1/3$

The equation of a line can be expressed as

$y = m x + b$ $y=mx+b$

You are given

$y = - 1$ $y=-1$

$x = 2$ $x=2$

$m = - \frac{1}{3}$ $m=-1/3$

Plugging each of these into the equation of a line gives us

$- 1 = - \frac{1}{3} (2) + b$ $-1=-1/3 (2)+b$

$- 1 + \frac{2}{3} = b$ $-1+2/3=b$

$b = - \frac{1}{3}$ $b=-1/3$

Finally, rewrite the linear equation with slope, $m$ $m$ , and slope intercept $b$ $b$ .

$y = - \frac{1}{3} x - \frac{1}{3}$ $y=-1/3x-1/3$