How do you solve and write the following in interval notation: #-16x - 8 ≤ -4(3x +1)#?
1 Answer
Jun 15, 2017
Explanation:
#"distribute the bracket on the right side"#
#-16x-8<= -12x-4#
#"add 16x to both sides"#
#cancel(-16x)cancel(+16x)-8<= -12x+16x-4#
#rArr-8<= 4x-4#
#"add 4 to both sides"#
#-8+4<= 4xcancel(-4)cancel(+4)#
#rArr-4<= 4x#
#"divide both sides by 4"#
#-4/4<=(cancel(4) x)/cancel(4)#
#rArr-1<=xrArrx>=-1#
#"in interval notation " [-1,+oo)#
