How do you solve #T+28+T=4(T-13)#?

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Answer 1 · 2017-06-15T23:52:44

#T = 40#

#T + 28 + T = 4 (T-13)#

#T + 28 + T = 4T - 52#

#T + T = 4T - 52 - 28#

#T + T - 4T = - 52 - 28#

#- 2T = - 52 - 28#

#- 2T = -80#

#T = -80 ÷ -2#

#color(blue)(T = 40#

Now we can put #40# in for #T# to prove our answer.

#40 + 28 + 40 = 4 (40 -13)#

#68 + 40 = 4 (40 -13)#

#68 + 40 = 4 xx 27#

#68 + 40 = 108#

#108 = 108#