Question

How do you graph `(x+3)^2+(y-2)^2=9`?

Answer 1

Please see below.

Explanation:

The equation `(x+3)^2+(y-2)^2=9` can be written as

`sqrt((x+3)^2+(y-2)^2)=3`

which indicates that the point `(x,y)` moves so that it is always at a distance of `3` from a point `(-3,2)`

Hence graph of `(x+3)^2+(y-2)^2=9` can be drawn by drawing a circle whose centre is `(-3,2)` and radius is `3`. It appears as shown below.
graph{((x+3)^2+(y-2)^2-9)((x+3)^2+(y-2)^2-0.03)=0 [-12.83, 7.17, -2.76, 7.24]}