How do you solve #3(c+5)=12# using the distributive property?

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Answer 1 · 2017-06-23T04:54:49

#c=-1#

What ever is outside the bracket, you multiply it with the terms inside the bracket.
You have to multiply #c# with #3# and #5# with #3#.

#therefore 3c+15=12#

#3c=-3#

#c=-1#

Answer 2 · 2017-06-23T05:12:46

#c=-1#

First, you distribute #3# to #c# and to #5#.
That would be #3(c)+3(5)=12#.

So, #3c+15=12#.

#3c=-3#
#c=-1#

Answer 3 · 2017-06-23T10:14:35

Using distributive property, it is,
#=3*c+3*5=12#
#=3c+15=12#
#=3c=12-15#
#=3c=-3#
#=c=(-3)/3#
#color(red)(=c=-1)#