Question

What is the solubility of oxygen in water? Give references for your answer. I saw some that said cc/gm or something like that.

Answer 1

We'll try, and I see Truong-Son N. has already tried; here is another attempt......

Explanation:

I think you mean `g*cm^-3` rather than `cm*g^-1`, and the former units mean precisely the same as `g*mL^-1`. Why?

`1*cm^3=(1xx10^-2*m)^3`. Why? Because the prefix `"centi"-=10^-2`. And thus............

`1*cm^3=(1xx10^-2*m)^3=1xx10^-6*m^3`.

Sometimes I remember that `1*m^3` (which is a HUGE volume!), is `1000*L`, and that there are `10^3*cm^3` in a `L`. An equivalent term for the `"litre"` is `"cubic decimeter"`, `dm^3`.

And thus `1000*L=10^3*Lxx10^-6*m^3=1xx10^-3*m^3`.

Equivalently `1*L=1*dm^3=(1xx10^-1*m)^3=10^-3*m^3`, as required.

If I have muddied the waters, I apologize.........

Answer 2

Here's a good source.

Depends on what temperatures you want though, because this is experimentally determined.

Here's a graph based on the above reference, for the solubility of `"O"_2(g)` IN AIR in water from `0^@ "C"` to `40^@ "C"` in `0.5^@ "C"` increments at `"760 torr"` atmospheric pressure.

For pure oxygen in water, divide the solubility by the mol fraction of oxygen in air, `0.21`:

Here's the data for oxygen in air, in one spreadsheet page:

The units are milligrams per liter of solution for the solubility. Or, another option is that I've also converted the solubility to molarity:

`cancel"mg"/"L" xx cancel"1 g"/(1000 cancel"mg") xx "1 mol O"_2/(31.998 cancel"g") = "mol O"_2/"L soln"`

And also the pure oxygen version: