Question

How many grams of `CO_2` are produced when 88 g of `O_2` are reacted with an excess of ethane?

Answer 1

69g of `CO_2`

Explanation:

Ethane's formula is `C_2H_6`. These products and reactants are common in combustion reactions, below is the balanced reaction. This is the key to solving this problem.

`2C_2H_6+7O_2 to 6H_2O+ 4CO_2`

The question tells us `C_2H_6` is the excess reactant, thus `O_2` is the limiting reactant.

`88g((O_2)/(32g))((4CO_2)/(7O_2))((44.01g)/(CO_2)) = 69g`