How do you find the slope that is perpendicular to the line #9x+3y=0#?

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Answer 1 · 2017-06-25T08:40:07

The slope is #=1/3#

Let's rewrite the equation

#9x+3y=0#

#3y=-9x#

#y=-3x#

The slope of a line with equation

#y=mx+c#

is #=m#

Here, we have #m=-3#

The slope of the line #m'# perpendicular to another line is

#mm'=-1#

#m'=-1/m=(-1)/(-3)=1/3#