What is the equation of the line that has a slope of 5 and goes through (0, -10)?

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Answer 1 · 2017-06-26T18:53:53

$y = 5 x - 10$ $y=5x-10$

The point slope form of an equation is

$y - y_{1} = m (x - x_{1})$ $y-y_1=m(x-x_1)$

The slope is $m = 5$ $m=5$ and the point is $(0, - 10)$ $(0,-10)$ .

Plugging these into the point slope form is

$y - (- 10) = 5 (x - 0)$ $y-(-10)=5(x-0)$

Simplifying

$y + 10 = 5 x$ $y+10=5x$

Subtracting $10$ $10$ from both sides gives

$y = 5 x - 10$ $y=5x-10$