What is the standard form of the equation of the parabola with a directrix at x=6 and a focus at (9,5)?

1 Answer
Jun 28, 2017

#6x=y^2-10y+70#

Explanation:

Parabola is the locus of a point which moves so that its distance from a given point called focus and a given line called directrix is always same.

Let the point on parabola be #(x,y)#. Here focus is #(9,5)# and its distance from focus is #sqrt((x-9)^2+(y-5)^2)#.

And as directrix is #x=6# and distance of #(x,y)# from #x=6# is #|x-6|#. Hence equation of parabola is

#(x-9)^2+(y-5)^2=(x-6)^2#

or #x^2-18x+81+y^2-10y+25=x^2-12x+36#

or #cancelx^2+81+y^2-10y+25-36=cancelx^2+18x-12x#

or #6x=y^2-10y+70#

or #x=1/6(y^2-10y+70)#

graph{(y^2-10y+70-6x)(x-6)((x-9)^2+(y-5)^2-0.03)=0 [-0.83, 19.17, -0.36, 9.64]}