Question

Question #970f7

Answer 1

NO

Explanation:

Answer: No
First solve the system of 2 linear equations, meaning find the coordinates of the intersection.
3x + 4 = - x - 4
4x = - 8 --> x = - 2, and
y = 3x + 4 = - 6 + 4 = - 2
Intersection M (-2, -2)
Next, find out if (-2, -2) satisfied the system of 2 quadratic inequalities, by replacing (-2, -2) in these inequalities. This means to find out if M is located in the solution set areas of these 2 inequalities.
a. `y > 2x^2 - 6`
-2 > 8 - 6 = 2 . Not true
b. `y <= - x^2 + x + 6`
`- 2 <= - 4 - 2 + 6 = 0` . Not true.
Therefore, the solution (-2, -2) of the linear system is not a solution of the quadratic inequality system.