Question

How do you solve `\log _{2}(2x-9)=3`?

Answer 1

`x=8.5`

Explanation:

As `log_2(2x-9)=3`, we have

`2x-9=2^3`

or `2x-9=8`

or `2x=8+9=17`

i.e. `x=17/2=8.5`