What is the equation of the line that contains #(8,-1)# and is parallel to #6x-5y=2#?

Question

414 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-30T16:14:31

Equation of line is #6x-5y=53#.

Equation of a line parallel to #ax+by=c# is #ax+by=k#

Hence, equation of a line parallel to #6x-5y=2# is

#6x-5y=k#

As it passes through #(8,-1)#

#6xx8-5xx(-1)=k#

i.e. #k=48+5=53#

Hence equation of line is #6x-5y=53#.