Question

How do you find `lim root3(x+2)` as `x->oo`?

Answer 1

Substitute `y=x+2`.

As:

`lim_(x->oo) y = lim_(x->oo) x+2 = oo`

Then:

`lim_(x->oo) root(3)(x+2) = lim_(y->oo) root(3)y = +oo`