Question

How do you solve `(9x - 2) ^ { 2} + 4= 0`?

Answer 1

`x = (2(1 +- i))/9`

Explanation:

`(9x - 2)^2 + 4 = 0`
`(9x - 2)^2 = - 4 = 4i^2`
There are 2 imaginary roots:
`9x - 2 = +- 2i`
`9x = 2 +- 2i`
`x = (2(1 +- i))/9`