How do you find the compositions given $f (x) = x^{3} + 2$ $f(x)=x^3+2$ and $g (x) = \sqrt[3]{x - 2}$ $g(x)=root3(x-2)$ ?

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How do you find the compositions given $f (x) = x^{3} + 2$ $f(x)=x^3+2$ and $g (x) = \sqrt[3]{x - 2}$ $g(x)=root3(x-2)$ ?

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Answer 1 · 2017-07-09T04:02:23

fg(x) = x and gf(x) = x

Explanation:

I think that these two functions are the inverse of each other. You can check this by letting y = f(x) and rearranging to make x the subject.
If you then make a composite function, you will get the answer above by replacing x with the other function.

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How do you find the compositions given $f (x) = x^{3} + 2$ $f(x)=x^3+2$ and $g (x) = \sqrt[3]{x - 2}$ $g(x)=root3(x-2)$ ?

1 Answer

Explanation:

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How do you find the compositions given f(x)=x3+2f(x)=x^3+2 and g(x)=3√x−2g(x)=root3(x-2)?

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How do you find the compositions given $f (x) = x^{3} + 2$ $f(x)=x^3+2$ and $g (x) = \sqrt[3]{x - 2}$ $g(x)=root3(x-2)$ ?