A square is inscribed in another square such that each vertex of inner square divides the side of the outside square into intervals of length #x# and #y# so that #x > y#. Find the ratio of inscribed square to outer square?
1 Answer
Jul 11, 2017
Please see below.
Explanation:
As a square is inscribed in another square such that each vertex of inner square divides the side of the outside square into intervals of length
It is apparent that each side of outer square is
Further using Pythagoras theorem, each side of inner square is
Hence, area of outer square exceeds that of inner square by
and ratio of inscribed square to outer square is