Find the formula weight of #"Ca"("C"_6"H"_12"NO"_3"S")_2#?

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Answer 1 · 2017-07-13T10:18:05

#396#

#Ca = 40#

#C = 12#

#H = 1#

#N = 14#

#S = 32#

#O = 16#

So

# = 40 + [(12 xx 6) + (1 xx 12) + 14 + 32 + (16 xx 3)] xx 2#

# = 40 + [72 + 12 + 14 + 32 + 48] xx 2#

# = 40 + 178 xx 2#

# = 396#