How do you find the derivative of # (ln(x^2))/x^2#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer VinÃcius Ferraz Jul 13, 2017 #2 * frac{1 - ln x^2}{x^3}# Explanation: #D_x ln(x^2)/x^2 = frac{x^2 D_x ln x^2 - ln x^2 D_x x^2}{x^4}# # = frac{x^2 1/x^2 D_x x^2 - 2x ln x^2}{x^4}# # = frac{2x - 2x ln x^2}{x^4}# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1167 views around the world You can reuse this answer Creative Commons License