How do you solve the equation #sinB=9/11#?
1 Answer
Jul 13, 2017
Explanation:
#sinB=9/11#
#rArrB=sin^-1(9/11)=54.9^@larrcolor(red)" related acute angle"#
#"since "sinB>0" then B lies in first/second quadrants"#
#rArrB=54.9" or " (180-54.9)^@=125.1^@#