Question

Question #f5e2e

Answer 1

I got `13.6m/s^2` in opposite direction to the car motion (a deceleration).

Explanation:

We can use the Kinematic relationship:

`v_f=v_i+at`

with:

`v_f=0` final velocity;
`v_i=45m/s` initial velocity;
`t=3.3s` time;
`a=`acceleration.

We get:

`0=45+3.3a`

rearranging:

`a=-45/3.3=-13.6m/s^2`

opposite to the movement and decelerating the car.