How do you solve #5x + 12x + 6= 0#?

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Answer 1 · 2017-07-16T21:31:24

See a solution process below:

First, factor out and combine like terms on the left side of the equation:

#(5 + 12)x + 6 = 0#

#17x + 6 = 0#

Next, subtract #color(red)(6)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#17x + 6 - color(red)(6) = 0 - color(red)(6)#

#17x + 0 = -6#

#17x = -6#

Now, divide each side of the equation by #color(red)(17)# to solve for #x# while keeping the equation balanced:

#(17x)/color(red)(17) = -6/color(red)(17)#

#(color(red)(cancel(color(black)(17)))x)/cancel(color(red)(17)) = -6/17#

#x = -6/17#