Question #b80b1 Chemistry Acids and Bases pH calculations 1 Answer Andrea B. · Ernest Z. · Nathan L. Jul 17, 2017 #[OH^-] = 3 xx 10^(-12)# Explanation: Since pH + pOH = 14 for all the aqueous solutions pOH = 14-pH = 11,5 Since in first approximation #pOH = -log[OH^-]# therefore #[OH^-] = 10^(-pOH) = 10^(-11,5) = 3 xx 10^(-12)# Answer link Related questions How do you determine ph of a solution? How do you determine pH at an equivalence point? How do you determine pH from molarity? What does alkalinity mean? What is a base? How do acid base indicators change color? What is a neutral pH? How does alkalinity affect pool water? Why is pH important in drinking water? How can I calculate the pH of a solution? See all questions in pH calculations Impact of this question 1396 views around the world You can reuse this answer Creative Commons License
