How can you simplify #sin^4a + cos^4a#?
1 Answer
Jul 17, 2017
Explanation:
Note that
#(sin^2a + cos^2a)^2 = sin^4a + 2sin^2acos^2a + cos^4a#
We see that
#1 = sin^4a + 2sin^2acos^2a + cos^4a#
Therefore,
#sin^4a + cos^4a = 1 - 2sin^2acos^2a#
Hopefully this helps!