At room temperature, an oxygen molecule, with mass of #5.31 x 10^-26 kg#, typically has a KE of about #6.21 x 10-21# J. How fast is the molecule moving? Physics Work and Energy Energy 1 Answer IDKwhatName Jul 18, 2017 #484ms^(-1)# Explanation: #E_k=(mv^2)/2=6.21*10^(-21)J# #6.21*10^(-21)=(5.31*10^(-26)v^2)/2# #v=sqrt((2(6.21*10^(-21)))/(5.31*10^(-26)))=483.630339~~484ms^(-1)# Answer link Related questions How do matter and energy interact? Question #50ca2 Question #242cf Question #5038d Question #50391 What is potential energy? Question #d6576 Question #50cae Question #50cb2 Question #50cb6 See all questions in Energy Impact of this question 20289 views around the world You can reuse this answer Creative Commons License