How do you differentiate #f(x)=1-(3x-3)^2# using the chain rule.? Calculus Basic Differentiation Rules Chain Rule 1 Answer Καδήρ Κ. Jul 18, 2017 So let's use the chain rule Explanation: #f(x)=1-(3x-3)^2# #f'(x)=-2(3x-3)*(3x-3)'=-2(3x-3)*3=# #-6(3x-3)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1555 views around the world You can reuse this answer Creative Commons License