How do you differentiate $f(x)=3sqrt(tan4x^2)$ using the chain rule?

Question

1768 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-18T21:09:22

$f'(x)=(12x)/(cos^2 4x^2 sqrt(tan4x^2))$

$f'(x)=3/(2sqrt(tan4x^2))*(tan4x^2)'=$

$3/(2sqrt(tan4x^2))*1/(cos^2 4x^2)(4x^2)'=$

$3/(2sqrt(tan4x^2))*1/(cos^2 4x^2)*8x=$

$(12x)/(cos^2 4x^2 sqrt(tan4x^2))$

How do you differentiate f(x)=3sqrt(tan4x^2)f(x)=3sqrt(tan4x^2) using the chain rule?