How do you divide $(2 x^{3} + 3 x^{2} - 8 x + 3) \div (x + 3)$ $(2x^3+3x^2-8x+3)div(x+3)$ ?

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How do you divide $(2 x^{3} + 3 x^{2} - 8 x + 3) \div (x + 3)$ $(2x^3+3x^2-8x+3)div(x+3)$ ?

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Answer 1 · 2017-07-20T08:32:07

$\frac{2 x^{3} + 3 x^{2} - 8 x + 3}{x + 3} = 2 x^{2} - 3 x + 1$ $(2x^3+3x^2-8x+3)/(x+3)=2x^2-3x+1$

Explanation:

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So

$\frac{2 x^{3} + 3 x^{2} - 8 x + 3}{x + 3} = 2 x^{2} - 3 x + 1$ $(2x^3+3x^2-8x+3)/(x+3)=2x^2-3x+1$

Answer 2 · 2017-07-20T08:40:46

$2 x^{2} - 3 x + 1$ $2x^2-3x+1$

Explanation:

$one way is to use the divisor as a factor in the numerator$ $"one way is to use the divisor as a factor in the numerator"$

$consider the numerator$ $"consider the numerator"$

$2 x^{2} (x + 3) - 6 x^{2} + 3 x^{2} - 8 x + 3$ $color(red)(2x^2)(x+3)color(magenta)(-6x^2)+3x^2-8x+3$

$= 2 x^{2} (x + 3) - 3 x (x + 3) + 9 x - 8 x + 3$ $=color(red)(2x^2)(x+3)color(red)(-3x)(x+3)color(magenta)(+9x)-8x+3$

$= 2 x^{2} (x + 3) - 3 x (x + 3) + 1 (x + 3) - 3 + 3$ $=color(red)(2x^2)(x+3)color(red)(-3x)(x+3)color(red)(+1)(x+3)color(magenta)(-3)+3$

$= 2 x^{2} (x + 3) - 3 x (x + 3) + 1 (x + 3) + 0$ $=color(red)(2x^2)(x+3)color(red)(-3x)(x+3)color(red)(+1)(x+3)+0$

$\Rightarrow \frac{2 x^{3} + 3 x^{2} - 8 x + 3}{x + 3}$ $rArr(2x^3+3x^2-8x+3)/(x+3)$

$=(cancel((x+3))(2x^2-3x+1))/(cancel((x+3))$

$=2x^2-3x+1$

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How do you divide $(2 x^{3} + 3 x^{2} - 8 x + 3) \div (x + 3)$ $(2x^3+3x^2-8x+3)div(x+3)$ ?

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How do you divide (2x^3+3x^2-8x+3)div(x+3)(2x3+3x2−8x+3)÷(x+3)(2x^3+3x^2-8x+3)div(x+3)?

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How do you divide $(2 x^{3} + 3 x^{2} - 8 x + 3) \div (x + 3)$ $(2x^3+3x^2-8x+3)div(x+3)$ ?