How do you solve #abs(2y+7)=7#?

1 Answer
Jul 20, 2017

As the absolute value of #2y+7=7#, then #2y+7=+-7#, as abs(), takes the magnitude of the number, whether its positive or negative, abs(), makes it positive.

So, either #2y+7=7#, or #2y+7=-7#

Let's solve #2y+7=7# first:
We take 7 from both sides first- #2y+7-color(red)(7)=7-color(red)(7)-=2y=0#

Then we divide both sides by 2 - #(2y)/color(red)(2)=0/color(red)(2)-=y=0#

Now, let's solve for #2y+7=-7#:
We take 7 from both sides first- #2y+7-color(red)(7)=-7-color(red)(7)-=2y=-14#

Then we divide both sides by 2 - #(2y)/color(red)(2)=-14/color(red)(2)-=y=-7#