Question

An object moves according to the equation `y=1/(t+2),y>=0`, how do you find the velocity as a function of t?

Answer 1

`v(t)=(dy)/(dt)=-1/((t+2)^2`

Explanation:

It is apparent that the position of the object is given by `y=1/(t+2)`, where `y>=0`

Therefore velocity is given by `v(t)=(dy)/(dt)=-1/((t+2)^2`